Prueba
SELECT SUM(f.qty) used_times,
COALESCE(i.ingr_code, f.food_code) code,
COALESCE(i.name, f.name) name,
SUM(COALESCE(i.qty, 1) * f.qty) qty,
COALESCE(i.meas, f.meas) meas
FROM usedfood f LEFT JOIN ingredients i
ON f.food_code = i.food_code
GROUP BY i.ingr_code, i.name
Salida:
| USED_TIMES | CODE | NAME | QTY | MEAS | ---------------------------------------------------- | 2 | 173 | ketchup | 2 | pcs | | 2 | 1130 | corned beef | 80 | gramm | | 2 | 1135 | laurel | 0.8 | gramm | | 2 | 1136 | clove | 2 | gramm | | 2 | 1138 | tomato | 160 | gramm | | 3 | 1139 | mustard | 15 | gramm | | 3 | 1140 | fresh egg | 150 | gramm | | 8 | 1144 | salt | 3.4 | gramm | | 5 | 1256 | spaghetti rinf | 375 | gramm | | 8 | 1258 | oil | 362 | gramm |
Aquí está SQLFiddle demostración
