intente crear una cadena de conexión de esta manera:
MySqlConnectionStringBuilder conn_string = new MySqlConnectionStringBuilder();
conn_string.Server = "mysql7.000webhost.com";
conn_string.UserID = "a455555_test";
conn_string.Password = "a455555_me";
conn_string.Database = "xxxxxxxx";
using (MySqlConnection conn = new MySqlConnection(conn_string.ToString()))
using (MySqlCommand cmd = conn.CreateCommand())
{ //watch out for this SQL injection vulnerability below
cmd.CommandText = string.Format("INSERT Test (lat, long) VALUES ({0},{1})",
OSGconv.deciLat, OSGconv.deciLon);
conn.Open();
cmd.ExecuteNonQuery();
}