Si está utilizando consultas sin procesar, solo necesita fusionar los datos. Algo como esto debería funcionar,
def merge_order_data_and_detail(orders, details):
"""Group details by order_id and merge it in orders."""
# create dictionary key:order_id value:[order_detail_data]
dic = {}
for d in details:
if d['order_id'] not in dic:
dic[d['order_id']] = []
dic[d['order_id']].append(d)
# iterate orders and add details
for o in orders:
if o['order_id'] in dic:
o['order_detail_data'] = dic[o['order_id']]
orders = [
{
"order_id": 1,
"user_id": 5
},
{
"order_id": 2,
"user_id": 50
}
]
details = [
{
"order_detail_id": 1,
"order_id": 1,
"user_id": 5,
"product_id": 202
},
{
"order_detail_id": 2,
"order_id": 1,
"user_id": 5,
"product_id": 203
},
{
"order_detail_id": 3,
"order_id": 2,
"user_id": 50,
"product_id": 402
},
{
"order_detail_id": 4,
"order_id": 2,
"user_id": 50,
"product_id": 403
}
]
merge_order_data_and_detail(orders, details)
print(orders)
Resultado:
[{'order_id': 1, 'user_id': 5, 'order_detail_data': [{'order_detail_id': 1, 'order_id': 1, 'user_id': 5, 'product_id': 202}, {'order_detail_id': 2, 'order_id': 1, 'user_id': 5, 'product_id': 203}]}, {'order_id': 2, 'user_id': 50, 'order_detail_data': [{'order_detail_id': 3, 'order_id': 2, 'user_id': 50, 'product_id': 402}, {'order_detail_id': 4, 'order_id':
2, 'user_id': 50, 'product_id': 403}]}]
Elimino muchas órdenes y atributos de detalles solo para simplificar la prueba.
No tengo la imagen completa, pero debería pensar en usar modelos de Django si aún no lo está usando. Es la manera de aprovechar todo el potencial del framework.
Espero que ayude.
