PHP:cómo mostrar una variable (a) dentro de otra variable (b) cuando la variable (b) contiene texto

Es mejor que uses sprintf() aquí.

$string = "%s is the name of a recently formed company hoping to take over the lucrative hairdryer design %s.";

$teamName = "My Company";
$sector = "sector";

echo sprintf($string, $teamName, $sector);
// My Company is the name of a recently formed company hoping to take over the lucrative hairdryer design sector.

En su base de datos, almacena $string . Utilice sprintf() para sustituir los valores de las variables.