Puede fusionar las 2 subconsultas en 1:
SELECT MAX(c.cust_id) AS max_nh_cust_id,
MAX(a.avail_balance) AS max_nh_avail_balance
FROM account a INNER JOIN customer c
ON a.cust_id = c.cust_id
WHERE c.state = 'NH'
y únete así:
SELECT a.cust_id
FROM account a
INNER JOIN customer c ON a.cust_id = c.cust_id
INNER JOIN (
SELECT MAX(c.cust_id) AS max_nh_cust_id,
MAX(a.avail_balance) AS max_nh_avail_balance
FROM account a INNER JOIN customer c
ON a.cust_id = c.cust_id
WHERE c.state = 'NH'
) t ON c.cust_id > t.max_nh_cust_id AND a.avail_balance > t.max_nh_avail_balance
WHERE c.state = 'MA'
Vea la demostración
.
Resultados:
> | cust_id |
> | ------: |
> | 13 |