Otro enfoque sería -
SELECT housing_id
FROM mytable
WHERE facility_id IN (4,7)
GROUP BY housing_id
HAVING COUNT(DISTINCT facility_id) = 2
ACTUALIZAR - inspirado por el comentario de Josvic, decidí hacer más pruebas y pensé en incluir mis hallazgos.
Uno de los beneficios de usar esta consulta es que es fácil de modificar para incluir más ID_instalaciones. Si desea encontrar todos los identificadores de vivienda que tienen identificadores de instalaciones 1, 3, 4 y 7, simplemente haga -
SELECT housing_id
FROM mytable
WHERE facility_id IN (1,3,4,7)
GROUP BY housing_id
HAVING COUNT(DISTINCT facility_id) = 4
El rendimiento de estas tres consultas varía enormemente según la estrategia de indexación empleada. No pude obtener un rendimiento razonable, en mi conjunto de datos de prueba, de la versión de subconsulta dependiente, independientemente de la indexación utilizada.
La solución de unión automática proporcionada por Tim funciona muy bien con índices de una sola columna separados en las dos columnas, pero no funciona tan bien a medida que aumenta el número de criterios.
Aquí hay algunas estadísticas básicas en mi tabla de prueba - 500k filas - 147963 id_vivienda con valores potenciales para id_instalación entre 1 y 9.
Estos son los índices utilizados para ejecutar todas estas pruebas -
SHOW INDEXES FROM mytable;
+---------+------------+---------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+
| Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type |
+---------+------------+---------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+
| mytable | 0 | UQ_housing_facility | 1 | housing_id | A | 500537 | NULL | NULL | | BTREE |
| mytable | 0 | UQ_housing_facility | 2 | facility_id | A | 500537 | NULL | NULL | | BTREE |
| mytable | 0 | UQ_facility_housing | 1 | facility_id | A | 12 | NULL | NULL | | BTREE |
| mytable | 0 | UQ_facility_housing | 2 | housing_id | A | 500537 | NULL | NULL | | BTREE |
| mytable | 1 | IX_housing | 1 | housing_id | A | 500537 | NULL | NULL | | BTREE |
| mytable | 1 | IX_facility | 1 | facility_id | A | 12 | NULL | NULL | | BTREE |
+---------+------------+---------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+
La primera consulta probada es la subconsulta dependiente -
SELECT SQL_NO_CACHE DISTINCT housing_id
FROM mytable
WHERE housing_id IN (SELECT housing_id FROM mytable WHERE facility_id=4)
AND housing_id IN (SELECT housing_id FROM mytable WHERE facility_id=7);
17321 rows in set (9.15 sec)
+----+--------------------+---------+-----------------+----------------------------------------------------------------+---------------------+---------+------------+--------+---------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+---------+-----------------+----------------------------------------------------------------+---------------------+---------+------------+--------+---------------------------------------+
| 1 | PRIMARY | mytable | range | NULL | IX_housing | 4 | NULL | 500538 | Using where; Using index for group-by |
| 3 | DEPENDENT SUBQUERY | mytable | unique_subquery | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | func,const | 1 | Using index; Using where |
| 2 | DEPENDENT SUBQUERY | mytable | unique_subquery | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | func,const | 1 | Using index; Using where |
+----+--------------------+---------+-----------------+----------------------------------------------------------------+---------------------+---------+------------+--------+---------------------------------------+
SELECT SQL_NO_CACHE DISTINCT housing_id
FROM mytable
WHERE housing_id IN (SELECT housing_id FROM mytable WHERE facility_id=1)
AND housing_id IN (SELECT housing_id FROM mytable WHERE facility_id=3)
AND housing_id IN (SELECT housing_id FROM mytable WHERE facility_id=4)
AND housing_id IN (SELECT housing_id FROM mytable WHERE facility_id=7);
567 rows in set (9.30 sec)
+----+--------------------+---------+-----------------+----------------------------------------------------------------+---------------------+---------+------------+--------+---------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+---------+-----------------+----------------------------------------------------------------+---------------------+---------+------------+--------+---------------------------------------+
| 1 | PRIMARY | mytable | range | NULL | IX_housing | 4 | NULL | 500538 | Using where; Using index for group-by |
| 5 | DEPENDENT SUBQUERY | mytable | unique_subquery | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | func,const | 1 | Using index; Using where |
| 4 | DEPENDENT SUBQUERY | mytable | unique_subquery | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | func,const | 1 | Using index; Using where |
| 3 | DEPENDENT SUBQUERY | mytable | unique_subquery | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | func,const | 1 | Using index; Using where |
| 2 | DEPENDENT SUBQUERY | mytable | unique_subquery | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | func,const | 1 | Using index; Using where |
+----+--------------------+---------+-----------------+----------------------------------------------------------------+---------------------+---------+------------+--------+---------------------------------------+
La siguiente es mi versión usando GROUP BY... HAVING COUNT...
SELECT SQL_NO_CACHE housing_id
FROM mytable
WHERE facility_id IN (4,7)
GROUP BY housing_id
HAVING COUNT(DISTINCT facility_id) = 2;
17321 rows in set (0.79 sec)
+----+-------------+---------+-------+---------------------------------+-------------+---------+------+--------+------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+---------+-------+---------------------------------+-------------+---------+------+--------+------------------------------------------+
| 1 | SIMPLE | mytable | range | UQ_facility_housing,IX_facility | IX_facility | 4 | NULL | 198646 | Using where; Using index; Using filesort |
+----+-------------+---------+-------+---------------------------------+-------------+---------+------+--------+------------------------------------------+
SELECT SQL_NO_CACHE housing_id
FROM mytable
WHERE facility_id IN (1,3,4,7)
GROUP BY housing_id
HAVING COUNT(DISTINCT facility_id) = 4;
567 rows in set (1.25 sec)
+----+-------------+---------+-------+---------------------------------+-------------+---------+------+--------+------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+---------+-------+---------------------------------+-------------+---------+------+--------+------------------------------------------+
| 1 | SIMPLE | mytable | range | UQ_facility_housing,IX_facility | IX_facility | 4 | NULL | 407160 | Using where; Using index; Using filesort |
+----+-------------+---------+-------+---------------------------------+-------------+---------+------+--------+------------------------------------------+
Y por último, pero no menos importante, la unión automática -
SELECT SQL_NO_CACHE a.housing_id
FROM mytable a
INNER JOIN mytable b
ON a.housing_id = b.housing_id
WHERE a.facility_id = 4 AND b.facility_id = 7;
17321 rows in set (1.37 sec)
+----+-------------+-------+--------+----------------------------------------------------------------+---------------------+---------+-------------------------+-------+-------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+--------+----------------------------------------------------------------+---------------------+---------+-------------------------+-------+-------------+
| 1 | SIMPLE | b | ref | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | IX_facility | 4 | const | 94598 | Using index |
| 1 | SIMPLE | a | eq_ref | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | test.b.housing_id,const | 1 | Using index |
+----+-------------+-------+--------+----------------------------------------------------------------+---------------------+---------+-------------------------+-------+-------------+
SELECT SQL_NO_CACHE a.housing_id
FROM mytable a
INNER JOIN mytable b
ON a.housing_id = b.housing_id
INNER JOIN mytable c
ON a.housing_id = c.housing_id
INNER JOIN mytable d
ON a.housing_id = d.housing_id
WHERE a.facility_id = 1
AND b.facility_id = 3
AND c.facility_id = 4
AND d.facility_id = 7;
567 rows in set (1.64 sec)
+----+-------------+-------+--------+----------------------------------------------------------------+---------------------+---------+-------------------------+-------+--------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+--------+----------------------------------------------------------------+---------------------+---------+-------------------------+-------+--------------------------+
| 1 | SIMPLE | b | ref | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | IX_facility | 4 | const | 93782 | Using index |
| 1 | SIMPLE | d | eq_ref | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | test.b.housing_id,const | 1 | Using index |
| 1 | SIMPLE | c | eq_ref | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | test.b.housing_id,const | 1 | Using index |
| 1 | SIMPLE | a | eq_ref | UQ_housing_facility,UQ_facility_housing,IX_housing,IX_facility | UQ_housing_facility | 8 | test.d.housing_id,const | 1 | Using where; Using index |
+----+-------------+-------+--------+----------------------------------------------------------------+---------------------+---------+-------------------------+-------+--------------------------+
