Esto se puede solucionar de dos formas:
Usando solo SQL:
SQL Fiddle:http://www.sqlfiddle.com/#!2 /19d46/14
SELECT case
when c.text_choice = (select min(text_choice) from choice c2 where c2.id = q.id) then name_question
else ""
end as name_question,
case
when c.text_choice = (select min(text_choice) from choice c2 where c2.id = q.id) then text_question
else ""
end as text_question,
c.text_choice
FROM question as q LEFT JOIN choice as c
ON q.id = c.id
order by q.id, c.text_choice;
Resultado:
Q1 Q1_text C1
C2
C3
Q2 Q2_text C4
C5
C6
También usando PHP:
En la visualización inicial, esto se puede lograr fácilmente a través de PHP y ordenando sus resultados por nombre_pregunta.
$query = ' SELECT q.name_question, q.text_question, c.text_choice'.
' FROM question as q '.
' LEFT JOIN choice as c ' .
' ON q.id_question = c.id_question ' order by q.name_question;
Al mostrar el resultado:
$current_nameQuestion = "";
foreach ($db->loadObjectList() as $obj){
if($current_nameQuestion==$obj->name_question)
{
echo " ".$obj->text_choice."</br>";
}
else
{
echo $obj->name_question." ".$obj->text_question." ".$obj->text_choice."</br>";
$current_nameQuestion = $obj->name_question;
}
}
El código PHP anterior, solo imprimirá los valores de 2 columnas cuando name_question
aún no se ha emitido.