Informe de Asistencia en MySql

Aquí hay un camino largo que debería funcionar como se esperaba:

SELECT
    Employee.emp_Name,
    '2011' AS `Year`,
    'Dec' AS `Month`,
    CASE (
        IF(
            DATE('1-12-2011') < DATE(Employee.Joining_Date)),
            '0' --Not joined yet
            IF (
                (SELECT COUNT(*) FROM Holiday WHERE DATE('1-12-2011') = DATE(Holiday.date)) = 1,
                '1', --National Holiday
                IF (
                    (SELECT COUNT(*) FROM Leave WHERE DATE('1-12-2011') > DATE(Leave.to_Date) AND DATE('1-12-2011') < DATE(Leave.from_Date) AND Leave.Emp_Id = Employee.emp_id) = 1,
                    '2', --On Leave
                    IF(
                        (SELECT COUNT(*) FROM Doctor WHERE DATE('1-12-2011') > DATE(Doctor.Call_Date) AND Doctor.call_Done_By = Employee.emp_id) = 1 OR 
                        (SELECT COUNT(*) FROM Chemist WHERE DATE('1-12-2011') > DATE(Chemist.Call_Date) AND Chemist.call_Done_By = Employee.emp_id) = 1,
                        '3' --Visit Doctor or Chemist
                        '4' --Employee was at work
                    )
                )
            )
        )
    )
        WHEN 0 THEN 'N/A' --Not joined yet
        WHEN 1 THEN 'L' --National Holiday
        WHEN 2 THEN 'L' --On Leave
        WHEN 3 THEN 'S' --Visit Doctor or Chemist
        ELSE 'Y' --Employee was at work
    END AS `1`, --first day of month
    ... AS `2`, --repeat for second day of the month till max day of current month replace '1-12-2011' with each different day of month
    ...
    ... AS `30`
FROM
    Employee

Mi sugerencia es crear una vista que haga la declaración if para cada empleado, de esa manera su código será más fácil de mantener. Tenga en cuenta que este es un pseudocódigo que puede necesitar algunos cambios para ejecutarse.

Espero que esto ayude.