Basado en la solución con regexp split puede ejecutar la siguiente consulta.
Sin embargo, tenga en cuenta que debe conocer el número máximo de columnas resultantes por adelantado.
with t1 as (select 1 rn, 'Orcl, orcl, linux box, Pass, tablespace_name1, tablespace_name2' col from dual union all
select 2 rn, 'Orcl2, orcl2, linux box2, Pass2, tablespace_name12, tablespace_name22' col from dual),
t2 as (select rownum colnum from dual connect by level <= 6 /* (max) number of columns */)
select t1.rn, t2.colnum, rtrim(ltrim(regexp_substr(t1.col,'[^,]+', 1, t2.colnum))) col from t1, t2
where regexp_substr(t1.col, '[^,]+', 1, t2.colnum) is not null
order by rn,colnum;
Esto le da la vista de fila, columna y clave:
RN COLNUM COL
----- ---------- ------------------
1 1 Orcl
1 2 orcl
1 3 linux box
1 4 Pass
1 5 tablespace_name1
1 6 tablespace_name2
2 1 Orcl2
2 2 orcl2
2 3 linux box2
2 4 Pass2
2 5 tablespace_name12
2 6 tablespace_name22
Puede usar la consulta PIVOT para obtener el resultado en una tabla plana
with t1 as (select 1 rn, 'Orcl, orcl, linux box, Pass, tablespace_name1, tablespace_name2' col from dual union all
select 2 rn, 'Orcl2, orcl2, linux box2, Pass2, tablespace_name12, tablespace_name22' col from dual),
t2 as (select rownum colnum from dual connect by level <= 6 /* (max) number of columns */),
t3 as (select t1.rn, t2.colnum, rtrim(ltrim(regexp_substr(t1.col,'[^,]+', 1, t2.colnum))) col from t1, t2
where regexp_substr(t1.col, '[^,]+', 1, t2.colnum) is not null)
select * from t3
PIVOT (max(col) col for (colnum) in
(1 as "1",
2 as "2",
3 as "3",
4 as "4",
5 as "5",
6 as "6"))
order by rn;
RN 1_COL 2_COL 3_COL 4_COL 5_COL 6_COL
----- --------- --------- --------- --------- --------- ---------
1 Orcl orcl linux box Pass tablespace_name1 tablespace_name2
2 Orcl2 orcl2 linux box2Pass2 tablespace_name12 tablespace_name22
Nuevamente, como puede ver, debe enumerar todas las columnas resultantes en la consulta.
