Ayuda con la consulta CTE recursiva que se une a una segunda tabla

Pruebe este ejemplo, que le dará el resultado (1 fila de muestra)

id  Name    ParentID    Path    abbreviation    (No column name)
5   China   2   Asia/China  CN,AS   Asia/China:CN,AS

El ser TSQL

DECLARE @tbl TABLE ( 
     Id INT 
    ,[Name] VARCHAR(20) 
    ,ParentId INT 
    ) 

INSERT INTO @tbl( Id, Name, ParentId ) 
VALUES 
 (1, 'Europe', NULL) 
,(2, 'Asia',   NULL) 
,(3, 'Germany', 1) 
,(4, 'UK',      1) 
,(5, 'China',   2) 
,(6, 'India',   2) 
,(7, 'Scotland', 4) 
,(8, 'Edinburgh', 7) 
,(9, 'Leith', 8) 

; 
DECLARE @tbl2 table (id int, abbreviation varchar(10), tbl_id int)
INSERT INTO @tbl2( Id, Abbreviation, tbl_id ) 
VALUES 
 (100, 'EU', 1) 
,(101, 'AS', 2) 
,(102, 'DE', 3) 
,(103, 'CN', 5)

;WITH abbr AS (
    SELECT a.*, isnull(b.abbreviation,'') abbreviation
    FROM @tbl a
    left join @tbl2 b on a.Id = b.tbl_id
), abcd AS ( 
          -- anchor 
        SELECT  id, [Name], ParentID,
                CAST(([Name]) AS VARCHAR(1000)) [Path],
                cast(abbreviation as varchar(max)) abbreviation
        FROM    abbr
        WHERE   ParentId IS NULL 
        UNION ALL
          --recursive member 
        SELECT  t.id, t.[Name], t.ParentID, 
                CAST((a.path + '/' + t.Name) AS VARCHAR(1000)) [Path],
                isnull(nullif(t.abbreviation,'')+',', '') + a.abbreviation
        FROM    abbr AS t 
                JOIN abcd AS a 
                  ON t.ParentId = a.id 
       )
SELECT *, [Path] + ':' + abbreviation
FROM abcd