Su resultado deseado no está exactamente claro, pero puede usar tanto el UNPIVOT y PIVOT función para obtener el resultado
Si conoce el número de columnas, puede codificar los valores:
select *
from
(
select id,
'Instance'+cast(instance as varchar(10))+'_'+col col,
value
from
(
select id,
Instance,
Name,
cast(Size as varchar(50)) Size,
Tech
from yourtable
) x
unpivot
(
value
for col in (Name, Size, Tech)
) u
) x1
pivot
(
max(value)
for col in
([Instance0_Name], [Instance0_Size], [Instance0_Tech],
[Instance1_Name], [Instance1_Size], [Instance1_Tech],
[Instance2_Name], [Instance2_Size], [Instance2_Tech],
[Instance3_Name], [Instance3_Size], [Instance3_Tech])
) p
Consulte SQL Fiddle con demostración
Luego, si tiene un número desconocido de valores, puede usar sql dinámico:
DECLARE @query AS NVARCHAR(MAX),
@colsPivot as NVARCHAR(MAX)
select @colsPivot = STUFF((SELECT ','
+ quotename('Instance'+ cast(instance as varchar(10))+'_'+c.name)
from yourtable t
cross apply sys.columns as C
where C.object_id = object_id('yourtable') and
C.name not in ('id', 'instance')
group by t.instance, c.name
order by t.instance
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query
= 'select *
from
(
select id,
''Instance''+cast(instance as varchar(10))+''_''+col col,
value
from
(
select id,
Instance,
Name,
cast(Size as varchar(50)) Size,
Tech
from yourtable
) x
unpivot
(
value
for col in (Name, Size, Tech)
) u
) x1
pivot
(
max(value)
for col in ('+ @colspivot +')
) p'
exec(@query)
Consulte SQL Fiddle con demostración
Si el resultado no es correcto, edite su OP y publique el resultado que espera de las dos identificaciones que proporcionó.
