Desde las primeras versiones de su pregunta, parece que su XML en realidad está en diferentes filas en una tabla. Si ese es el caso, puedes usar esto.
update YourTable set
XMLText.modify('replace value of (/Identification/@Age)[1] with "40"')
where XMLText.value('(/Identification/@Age)[1]', 'int') = 30
Muestra de trabajo usando una variable de tabla.
declare @T table(XMLText xml)
insert into @T values('<Identification Name="John" Family="Brown" Age="30" />')
insert into @T values('<Identification Name="Smith" Family="Johnson" Age="35" />')
insert into @T values('<Identification Name="Jessy" Family="Albert" Age="60" />')
insert into @T values('<Identification Name="Mike" Family="Brown" Age="23" />')
insert into @T values('<Identification Name="Sarah" Family="Johnson" Age="30" />')
update @T set
XMLText.modify('replace value of (/Identification/@Age)[1] with "40"')
where XMLText.value('(/Identification/@Age)[1]', 'int') = 30
select *
from @T